Advanced Shellcoding Techniques

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Title: Advanced Shellcoding Techniques
 
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Date: July 25, 1997
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I think it's about time for some example code, so here it is: xorl %ecx,%ecx mul %ecx What is this shellcode doing? Well, it 0's out the %ecx register using the xor instruction, so we now know that %ecx is 0. Then it does a mul %ecx, which as we just learned, multiplies it's operand by the value in %eax, and then proceeds to store the result of this multiplication in EDX:EAX...
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Then it does a mul %ecx, which as we just learned, multiplies it's operand by the value in %eax, and then proceeds to store the result of this multiplication in EDX:EAX. So, regardless of %eax's previous contents, %eax must now be 0. However that's not all, %edx is 0'd now too, because, even though no overflow occurs, it still overwrites the %edx register with the sign bit(left-most bit) of %eax...
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